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-k^2+11k-24=0
We add all the numbers together, and all the variables
-1k^2+11k-24=0
a = -1; b = 11; c = -24;
Δ = b2-4ac
Δ = 112-4·(-1)·(-24)
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-5}{2*-1}=\frac{-16}{-2} =+8 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+5}{2*-1}=\frac{-6}{-2} =+3 $
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